Math, asked by nikhil6274, 1 year ago

find the factors of 3x²-9x-12/ 3x-12​

Answers

Answered by varun1594
4

find the factors of 3x²-9x-12/ 3x-12

➡ [3x ^ 2 - 9 x - 12 ] / [3x - 12] [ 3x ^ 2 - 12x + 3 x - 12 ] / [ 3 x - 12]

= [ 3x ( x - 4) + 3 ( x - 4)] / [ 3x - 12 ]

= [(3x + 3) ( x-4 ) ] / [ 3 x - 12 ]

= [ (3x + 3 ) (x - 4 ) ] / 3 (x - 4)

so, ( 3 x + 3 ) / 3

= 3 ( x +1) /3

= (x+1)

x = -1

Answered by Shahoodalam
3

 \frac{3x {}^{2} - 9x - 12 }{3x - 12}  \\  \frac{3x {}^{2}  - 12x + 3x - 12}{3x - 12}  \\  \frac{3x(x - 4) + 3(x - 4)}{3x - 12}  \\  \frac{(3x + 3)(x - 4)}{3(x - 4)}  \\  \frac{3x + 3}{3}  \\  \frac{3(x + 1)}{3}  \\ x + 1

I hope that will help you dear

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