Question

find the factors of 3xsquare+x​

Answer 1

Answer:

$x = 0$ or $x = -\frac{1}{3}$

Step-by-step explanation:

$3x^{2} +x = 0$

$x(3x+1) = 0$

$x = 0$ or $3x+1 = 0$

so

$x = 0$ or $x = -\frac{1}{3}$

Answer 2

Answer:-

Step-by-step explanation:-

3x² + x = 0

Take x as common from LHS

Factors of x

⇒ x (3x + 1) = 0

⇒ (x) (3x +1) = 0

Therefore, x = 0

Factor of 3x+1

⇒ 3x + 1 = 0

⇒ 3x = -1

⇒ x = -1/3

Therefore, The requred factors are x and 3x+1.