Question

Find the factors of 3z*z +9z + 6 ​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Step by step solution :

STEP

1

:

Equation at the end of step 1

((0 - 3z2) - 9z) - 6 = 0

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

-3z2 - 9z - 6 = -3 • (z2 + 3z + 2)

Trying to factor by splitting the middle term

3.2 Factoring z2 + 3z + 2

The first term is, z2 its coefficient is 1 .

The middle term is, +3z its coefficient is 3 .

The last term, "the constant", is +2

Step-1 : Multiply the coefficient of the first term by the constant 1 • 2 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 3 .

-2 + -1 = -3

-1 + -2 = -3

1 + 2 = 3 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 1 and 2

z2 + 1z + 2z + 2

Step-4 : Add up the first 2 terms, pulling out like factors :

z • (z+1)

Add up the last 2 terms, pulling out common factors :

2 • (z+1)

Step-5 : Add up the four terms of step 4 :

(z+2) • (z+1)

Which is the desired factorization