Math, asked by bbs22, 10 months ago

Find the factors of 6x^2-3-7x​

Answers

Answered by itspreet29
3

6x2-7x-3=0

6x2-9x +2x -3=0

3x(2x-3)+1(2x-3)=0

(3x+1)(2x-3)=0

3x=-1. , 2x=3

x=-1/3. , x=3/2

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Answered by NeverMind11
4

6x²-3-7x = 0

6x²-7x-3 = 0

6x²-9x+2x-3 = 0

3x(2x-3)+1(2x-3)

(3x+1)(2x-3)

x = -1/3 and x = 3/2


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NeverMind11: :-)
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