Question

Find the factors of a^2(b+c)+b^2(c+a)+c^2(a+b)-2b^2c

Answer 1

Step-by-step explanation:

MOSFET01 avatar

a^2(b+c)+b^2(c+a)+c^2(a+b)+2abc

= a^2 b+ a^2c + b^2 c+ ab^2+c^2a+bc^2+2abc

= a(b^2+ 2bc+c^2) + a^2 b+ a^2c + b^2 c +bc^2

= a(b+c)^2 + a^2(b+c) + bc(b+c)

= (b+c) [ a^2 +a(b+c)+ bc]

= (b+c) (a +b)(c+a)