Find the factors of A and B of x² + 10x+ 21 in form of AB.With explanation
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Answer:
x² + 10x+ 21
or, x ^2 + 7x +3x +21
or, x ( x +7 ) +3 ( x+7)
or, (x+7)(x+3)
Answered by
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Step-by-step explanation:
x^+10x+21
(x^+3x)+(7x+21)
x(x+3)7(x+3)
(x+7)(x+3)
A=(x+7)=0
x=-7
B=(x+3)=0
x=-3
AB=-7(-3)
=21
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