Find the factors of ab(a²+b²-c²)+bc(a²+b²-c²)+ca(c²-a²-b²
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Step-by-step explanation:
Given that,
ab ( a² + b² - c² ) + bc (a²+ b² - c² ) + ca ( c² - a² - b² )
= ab ( a² + b² - c² ) + bc ( a² + b² - c² ) + ca [ - ( a² + b² - c² ) ]
= ab ( a² + b² - c² ) + bc ( a² + b² - c² ) - ca ( a² + b² - c² ) (∵ + × - = - )
= ( a² + b² - c² ) ( ab + bc - ca ) is the answer.
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