Question

find the Factors of b²-2b-48

Answer 1

Answer:

(b+6) and (b-8)

Step-by-step explanation:

$b^2-2b-48 = b^2+6b - 8b - 48 = b(b+6) - 8(b+6) = (b+6)(b-8)$

So, roots of this quadratic are - 6and 8.