find the factors of b²- 7b + 12
Answers
Answer:
Factoring b2-7b+12
The first term is, b2 its coefficient is 1 .
The middle term is, -7b its coefficient is -7 .
The last term, "the constant", is +12
Step-1 : Multiply the coefficient of the first term by the constant 1 • 12 = 12
Step-2 : Find two factors of 12 whose sum equals the coefficient of the middle term, which is -7 .
-12 + -1 = -13
-6 + -2 = -8
-4 + -3 = -7 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -4 and -3
b2 - 4b - 3b - 12
Step-4 : Add up the first 2 terms, pulling out like factors :
b • (b-4)
Add up the last 2 terms, pulling out common factors :
3 • (b-4)
Step-5 : Add up the four terms of step 4 :
(b-3) • (b-4)
Which is the desired factorization
Final result :
(b - 3) • (b - 4)
Step-by-step explanation:
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Answer:
Use the sum-product pattern :
² − 7 + 12
² − 3 − 4 + 12
Common factor from the two pairs :
² − 3 − 4 + 12
( − 3) − 4( − 3)
Rewrite in factored form :
( − 3) − 4 ( − 3)
( − 4 ) ( − 3)
Solution :
( − 4) ( − 3)