Question

find the factors of following polynomial​

Answer 1

Answer:

it is only try........

Step-by-step explanation:

may be correct or incorrect

Answer 2

Answer ::

(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)

~_~

$\huge\mathfrak\pink{Solution :-}$

☞$\displaystyle\sf\pink{2(x^2-6x)^2-8(x^2-6x+3)-40=0}$

☞$\displaystyle\tt\purple{Consider\: x^2-6x=p}$

$\ \implies$$\displaystyle\sf\red{2p^2-8(p+3)-40=0}$

$\ \implies$$\displaystyle\sf\red{2p^2-8p-24-40=0}$

$\ \implies$$\displaystyle\sf\red{2p^2-8p-64=0}$

$\ \implies$$\displaystyle\sf\red{p^2-4p-32=0}$

$\ \implies$$\displaystyle\sf\red{p^2-8p+4p-32}$

$\ \implies$$\displaystyle\sf\red{p(p-8)+4(p-8)=0}$

$\ \implies$$\displaystyle\sf\red{p=8\: and \: p=-4}$

$\ \implies$$\displaystyle\sf\purple{x^2-6x=8}$

$\ \implies$$\displaystyle\sf\pink{x^2-4x-2x-8=0}$

$\ \implies$$\displaystyle\sf\pink{x(x-4)-2(x-4)=0}$

$\ \implies$$\displaystyle\sf\pink{x=4 \ and \ x=2 \ is \:the\: solution }$

$\bigstar$$\displaystyle\boxed{\sf\pink{x=4 \ and \ x=2}}$