Math, asked by kulramya04, 8 days ago

Find the factors of
 \sqrt{5x {}^{2} }  + 6x +  \sqrt{5}

Answers

Answered by Pra79us
0

Answer:

52) \frac{4 \times \frac{?}{?} \times \frac{?}{?} }{?} \times \frac{?}{?} 15y \frac{555 \frac{ \frac{ \frac{ \frac{y \frac{ \frac{5y \sqrt{4 \sqrt{y \sqrt{y \sqrt{ \sqrt{ \sqrt{y \sqrt{y \sqrt{y \sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5} } } } } } } } } } } } } } }{?} }{?} \times \frac{?}{?} }{?} }{?} }{?} }{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} }{?}

Step-by-step explanation:

if one zero of the quadratic polynomial ( kx² + 3 X + K ) is 2 , then the value of k is if one zero of the quadratic polynomial ( kx² + 3 X + K ) is 2 , then the value of k is if one zero of the quadratic polynomial ( kx² + 3 X + K ) is 2 , then the value of k is#4\4%_&%

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