Question

Find the factors of the following expression a cube-0.216

Answer 1

Answer:

Let see your answer !!!!

\begin{gathered}a ^{3} - 0.216 \\ \\ = a ^{3} - (0.6) ^{3} \\ \\ = (a - 0.6)(a ^{2} + a \times 0.6 + 0.6 ^{2} ) \\ \\ = (a - 0.6)(a ^{2} + 0.6a + 0.36)\end{gathered}

a

3

−0.216

=a

3

−(0.6)

3

=(a−0.6)(a

2

+a×0.6+0.6

2

)

=(a−0.6)(a

2

+0.6a+0.36)

\begin{gathered}we \: applied \: this \: identity \\ \\ a ^{3} - b ^{3} = (a - b)(a ^{2} + ab + b ^{2})\end{gathered}

weappliedthisidentity

a

3

−b

3

=(a−b)(a

2

+ab+b

2

)

Thanks :)))))