Question

find the factors of the following using identities
(2t-1) (2t+1) (4t^2+1)
I want explanation with steps
do it fast please ​

Answer 1

Step-by-step explanation:

by factor theorem

a function be zero at that point. so

take

(2t-1) (2t+1) (4t^2+1)=0

so

2t-1=0 , 2t+1=0

t=1/2 , t=-1/2 '

, 4t^2+1 =0

t^2 = -1/4 where i is iota= √-1

t= ± √-1/4

t=-i/2 and t = i/2