Find the factors of the polynomial 3y2-2 y-1
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Answer:
(y-1) (3y+1)
Step-by-step explanation:
- 3y²-2y-1
- = 3y² - 3y + y - 1
- = 3y ( y-1 ) +1 (y-1 )
- = (3y+1) (y-1)
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