Math, asked by Paradox007000, 16 days ago

Find the factors of the polynomial given below (x^2 - 6x)^2 +12 (x^2 - 6x) +35​

Answers

Answered by bagkakali
0

Answer:

(x^2-6x)^2+12(x^2-6x)+35

let (x^2-6x)=a

then,

a^2+12a+35

=a^2+7a+5a+35

=a(a+7)+5(a+7)

=(a+7)(a+5)

putting the value of a

(x^2-6x+7)(x^2-6x+5)

=(x^2-6x+7)(x^2-5x-x+5)

=(x^2-6x+7){x(x-5)-1(x-5)}

=(x^2-6x+7)(x-5)(x-1)

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