Question

find the factors of the polynomial
${y}^{2} + 14 + 24$
​

Answer 1

Step-by-step explanation:

x2

−12xy+24y

2

=x

2

−12xy−2xy+24y

2

=x(x−12y)−2y(x−12y)

=(x−2y)(x−12y)

factor are,(x−2y),(x−12y)

Answer 2

$\LARGE{\underline{\sf{\red{ Aɴsᴡᴇʀ:}}}}$

ʏ² + 14 + 24

• 1 , 14 , 24
• Sum = 14
• Product = 24

━━━━━━━━━━━━━━━━━━━━━━━━━━

24 × 1 = 24

2 × 12 = 24 ✓

3 × 8 = 24

4 × 6 = 24

━━━━━━━━━━━━━━━━━━━━━━━━━━

ʏ² + 2ʏ + 12ʏ + 24

ʏ•ʏ + 2•ʏ + 2•2•3•ʏ + 2•3•2•2

(Tαkє common fαctors)

ʏ( ʏ + 2 ) + 2•2•3( ʏ + 2 )

ʏ( ʏ + 2 ) + 12( ʏ + 2 )

$\LARGE{\underline{\sf{\pink{( ʏ + 2 ) ( ʏ + 12 )}}}}$

Hᴏᴘᴇ Tʜɪs Hᴇʟᴘs Yᴏᴜ