Question

find the factors of the x2 + 5xy +4y2 ​

Answer 1

x^2+5xy+4y^2=0

x^2+4xy+xy+4y^2=0

x(x+4y)+y(x+4y)=0

(x+y)+(x+4y)=0

Therefore, x=-y,-4y

Or

y=-x,-x/4