Question

find the factors of x*3-6x*2+11x-6 by factor theorem

Answer 1

hey!

#your Ans
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put the Value of X = 1 which is factor of -6

so

==> (1)^3 -6(1)^2 +11 -6

==> 1 -6 +11 -6 =0

==> 12 -12 =0

==> 0

so (x-1) is a factor of the equation

now,

==> x^2 (x-1) -5x (x-1) +6 (x-1)

==> (x-1) (x^2 -5x +6)

==> (x-1) (x^2 -3x -2x +6)

==> (x-1) {x (x-3) -2(x-3) }

==> (x-1) (x-3) (x-2) Ans


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