Question

find the factors of x square+2x+1=0​

Answer 1

Step-by-step explanation:

x^2+2x+1=0

x^2+x+x+1=0

x(x+1)1(x+1)=0

(x+1)(x+1)=0

x=(-1,-1)

Answer 2

$\huge{ \underbrace{ \red{ \bf{SoLuTiOn}}}}$

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$✍ {x}^{2} + 2x + 1 = 0$

$✍Do \: LCM \: of \: (1,1) = 1 × 1$

$✍ {x}^{2} + x + x + 1 = 0$

$✍taking \: out \: commons$

$✍x(x + 1) + 1(x + 1) = 0$

$✍(x + 1)(x + 1) = 0$

$✍(x + 1 {)}^{2} = 0$

Or,

$✍x = - 1;x = - 1$

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Factors are (x + 1)²

Hope it helps.........

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