Question

Find the factors of (x – y)3 + (y – 2)3 + (z – x)3​

Answer 1

Answer:

x=−  1−y/ y  ,y  =1

 

 

 

y=−  1−x/ x  ,x  =1

Answer 2

Answer:

We know the corollary: if a+b+c=0 then a

3

+b

3

+c

3

=3abc

Using the above identity taking a=x−y, b=y−z and c=z−x, we have a+b+c=x−y+y−z+z−x=0 then the equation (x−y)

3

+(y−z)

3

+(z−x)

3

can be factorised as follows:

(x−y)

3

+(y−z)

3

+(z−x)

3

=3(x−y)(y−z)(z−x)

Hence, (x−y)

3

+(y−z)

3

+(z−x)

3

=3(x−y)(y−z)(z−x)

I HOPE HELP YOU

THANKS YOU ❤️