Question

Find the factors of x²+17x+72=0?

Answer 1

 $x^{2}$+17x+72=0.

=72*$x^{2}$= 72$x^{2}$.we have to get 72$x^{2}$ as the product of factors.



we have to get 17x if we subtract/add the factors.


so the factors are=8x and 9x.= 8x+9x = 17x. and 8x*9x= 72$x^{2}$.

so, $x^{2}$+8x+9x+72.
if we take common:

x(x+8) +9(x+8).

so the factors are-x+8, x+9....

         (or)
x+8= 0. so, x= -8.
x+9=o.so, x= -9

hope this helps u.n pls mark as brainliest........

Answer 2

x = (-8) or (-9)//<br /> Factors are, <br /> (x+8)(x+9)<br /> ............................<br />.......................<br /><br /><br /><br /><br />