Question

find the factors of x²+7x+12
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Answer 1

Answer:

Let zeros of cubic polynomial are α,β and γ. Then

α+β+γ=0

αβ+βγ+αγ=−7

αβγ=−6

Now, the required polynomial is

x

3

−(α+β+γ)x

2

+(αβ+βγ+αγ)x−(αβγ)

Therefore, the required polynomial is x

3

−(0)x

2

+(−7)x−(−6) i.e x

3

−7x+6

Answer 2

Answer:

(x-4) (x-3)

Step-by-step explanation:

x² - 7x - 12

= x² -3x - 4x -12

= x(x-3) - 4(x-3)

= (x-4)(x-3)