Math, asked by cprathimareddy, 4 months ago

find the factors of y square-7y+12​

Answers

Answered by naman44009
6

Answer:

Y

2

−7Y+12

=Y

2

−3y−4Y+12

=Y(Y−3)−4(Y−3)

=(Y−3)(Y−4)

⇒Y−3 is a factor of Y

2

−7Y+12

Answered by raghvendrark500
1

y²-7y+12

= y²-3y-4y+12

= y(y-3)-4(y-3)

= (y-4)(y-3)

so factors are

(y-4) &(y-3)

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