find the factors of y square-7y+12
Answers
Answered by
6
Answer:
Y
2
−7Y+12
=Y
2
−3y−4Y+12
=Y(Y−3)−4(Y−3)
=(Y−3)(Y−4)
⇒Y−3 is a factor of Y
2
−7Y+12
Answered by
1
y²-7y+12
= y²-3y-4y+12
= y(y-3)-4(y-3)
= (y-4)(y-3)
so factors are
(y-4) &(y-3)
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