Question

Find the factors of z^2 - 4z- 12​

Answer 1

Answer:

z2 - 4z-12

z2-6z+2z-12

z(z-6)+2(z-6)

(z+2)(z-6)

Answer 2

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

Given:

• z^2 - 4z - 12

To Find:

• Factors of the polynomial

Solution:

$\implies z^2 - 4z - 12 \\ \implies z^2 - 6z + 2z - 12 \:\:\:\:\:\:\:\:(\because -6*2=-12 \:\&\: -6+2=-4) \\ \implies z(z - 6) + 2(z - 6) \\ \bold{\implies (z - 6)(z + 2)} \\ Hence\:the\:factors\:are\:(z-6)\:\&\:(z+2)$

Hope it helps!!