Find the farthest distance of the point (1, 5) from the circle (x-1)^2 + (y+1)^2 = 16.
Answers
Given : circle (x-1)^2 + (y+1)^2 = 16.
point (1, 5)
To Find : farthest distance of the point (1, 5) from the circle
Solution:
(x - 1)² + ( y + 1)² = 16
=> (x - 1)² + ( y + 1)² = 4²
Center = 1 , - 1
Farthest distance of point ( 1, 5) from the circle
= Distance from center of circle + Radius
Center = (1 , - 1) , point ( 1, 5)
Distance from center of circle = √(1 - 1)² + (5 -(-1))² = 6
Radius = 4 cm
Farthest distance of point ( 1, 5) from the circle = 6 + 4 = 10 cm
and closest Distance of point ( 1, 5) from the circle = 6 - 4 = 2 cm
Farthest distance of point ( 1, 5) from the circle = 6 + 4 = 10 cm
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