Question

find the final ans plz

P = 12,000
R = 10%
n = 3​

Answer 1

Answer:

Rs. 16081

Step-by-step explanation:

$ci \: = \: p{((1 + \frac{r}{200}) }^{2n} - 1)$

$ci \: = \: 12000{((1 + \frac{10}{200}) }^{2 \times 3} - 1) \\ = \: 12000{((1 + \frac{1}{20}) }^{6} - 1) \\ = \: 12000{(( \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20 } \times \frac{21}{20} ) } - 1)$

$= 12000(1.34 - 1) \\ = 12000 \times 0.34 \\ = 16081$

Answer 2

Hey, Refer to the given attachment!