Find the final pH when 2 L of water is added to
0.5 L of 0.1 M HCI.
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Answered by
0
Answer:
Correct option is
B
13
Moles initially =0.5×01
=0.05mol Bu(OH)
2
On addition , new conc. =
newV
0.05
=
1
0.05
=0.05mol/lt
∴[OH
−
]=2×0.05 {diacids}
=0.1
∴pOH=1
∴pH=13
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