Question

Find the final temperature if we mix 10gm ice at -20°c into 5 gm steam at 100°c​

Answer 1

Answer:PHYSICS

5 Gm of steam at 100oC is passed into 6 gm of ice at 0oC. If the latent heats of steam and ice n cal per gm are 540 and 80 respectively, them the final temperature is:-

A .

0oC

B .

100oC

C .

50oC

D .

30oC

December 27, 2019Kanishka Momin

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ANSWER

Heat taken by ice to melt =6×80=480cal

Heat taken to raise the temperature of water by 1000C=6×1×100=600cal

Therefore, the total heat required by ice to raise up to 1000C=600+480=1080cal

Heat supplied by steam to condense =mL=5×540=2700cal

It means all the steam has not condensed

Let mass of the steam condensed =m

Then,

  m×540=1080

 m=5401080​

 m=2g

Now, the temperature of the mixture =1000C

Hence, this is the required solution

Explanation: