Question

find the final temperature of 3 kg water if 126000j of heat is absorbed by it at 42°C.(specific heat of water=4200j/kg¹) please answer this ....and thanks to those who answered my few questions​

Answer 1

Answer:

using

Q=ms(t2-t1)

126000=3×4200×(t2-42)

10 +42=t2

t2= 52 °C

which gives final temperature