Question

Find the final temperature of a copper rod. Whose area of cross-section changes from 10 m2 to 11 m2 due to heating. The copper rod is initially kept at 90 K. (Coefficient of superficial expansion is 0.0021 K)?​

Answer 1

Change in area ΔA = 11 – 10 = 1 m2

Initial temperature T1 = 90 K

Let Final temperature be T2 K

Ao = 10 m2

Coefficient of superficial expansion is

αA = 0.0021 / k

∆A/Ao = αA ΔT

1/10 = 0.0021 ΔT

∴ ΔT = 0.0021 x 10

= 0.021

T2 - T1 = 0.021

T2 – 90 = 0.021

∴ Final temperature T2 = 90.021 K

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