Question

Find the find a quadratic polynomial whose zeros are 2 + under root 3 and 2 minus under root 3

Answer 1

$\huge\bold{\underline{\underline{{Question:-}}}}$

Find the find a quadratic polynomial whose zeros are 2 + under root 3 and 2 minus under root 3?

$\huge\bold{\underline{\underline{{Answer:-:-}}}}$

$\bold{Given:-}\begin{cases}\sf{\underline{zeros\:\: are\:\: Given:-}}\\ \\ \sf {{1}^{st}\:\:\:\:\:2+\sqrt{3}}\\ \\ \ sf{{2}^{nd}\:\:\:\:2-\sqrt{3}}\end{{cases}$

$\large\underline{solution:-}[tex]</p><p>Let zeros be α and β</p><p>[tex]\green α = 2 + \sqrt{3}</p><p>\\ \\ \ red\β =2-\sqrt{3}$

so,

Let find some of zeros.

α + β = 2 +\sqrt{\cancel3}+ 2-

\sqrt{\cancel3} .\\ \\ \: \: \:

\: \: \: \: \: \: \: \: \: = 4.

$green{\underline{\α + β = 4---(1)}$

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$produce \:of \:zeros \:= α × β$ \\ \\ \:

\: \: \:\:\:\:\:\:\:\:\:\: = 2+\ sqrt{3})

\times( 2 - \sqrt{3} )\\ \\ \:

\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 4 - 3 \\ \\

\: \: \: \: \: \: \: \: \: \: \: \:\:\:\:

= 1.

$\red{\underline{\α × β = 1.-----(2)$

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$k({x}^{2}- sx +p) \\ \\ </p><p>k({x}^{2}- (4) x+1).\\ \\</p><p>k({x}^{2}-4x+1)$

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Answer 2

Answer:

hello dear.......

Step-by-step explanation:

i hope this answer is helpful to you................... :( :(