find the find the sum of n terms of an ap where n term is given by TN is equals to 3 minus 5 n
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First term of the AP is: 7–3(1) = 4
Second term is: 7–3(2)=1
Thus common difference is: second term- first term = 1–4 = -3
Therefore, the required sum= 25/2 [ 2*4 + (25–1)*-3]
On solving, we get, -800
Hence, the required sum is -800.
:)
Second term is: 7–3(2)=1
Thus common difference is: second term- first term = 1–4 = -3
Therefore, the required sum= 25/2 [ 2*4 + (25–1)*-3]
On solving, we get, -800
Hence, the required sum is -800.
:)
Adnamika1:
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:The first term of AP is :7-3 (1) 4
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