Question

find the first 15 terms of an AP 2,7,12​

Answer 1

Answer:

a4 = 17, a5 = 22, a6 = 27, a7 = 32, a8 = 37, a9 = 42, a10 = 47,

a11 = 52, a12 = 57, a13 = 62, a14 = 67, a15 = 72

Step-by-step explanation:

a1 = 2, a2 = 7, a3 = 12

So, d = 5

Now, a4 = 17, a5 = 22, a6 = 27, a7 = 32, a8 = 37, a9 = 42, a10 = 47,

a11 = 52, a12 = 57, a13 = 62, a14 = 67, a15 = 72.

Answer 2

Answer:- 72

Explanation:-

Given, AP = 2, 7, 12

a = 2

d = 5

Use Tn = a + (n - 1) d

• T15 = 2 + (15 - 1) 5
• T15 = 2 + 70
• T15 = 72

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