Question

Find the first 5 terms of geometric progression if a equals to 1024 and equals to 1 /2​

Answer 1

Step-by-step explanation:

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Answer 2

The first five terms of G.P if a=1024 and $r=\frac{1}{2}$ are 1024,512,256,128,64.

Step-by-step explanation:

Given : Geometric progression with a=1024 and $r=\frac{1}{2}$.

To find : The first five terms of G.P. ?

Solution :

The five terms of geometric series is in form $a,ar,ar^2,ar^3,ar^4$ .

Where, a=1024 and $r=\frac{1}{2}$.

First term is a=1024

Second term is $ar=(1024)(\frac{1}{2})=512$

Third term is $ar^2=(1024)(\frac{1}{2})^2=1024\times \frac{1}{4}=256$

Fourth term is $ar^3=(1024)(\frac{1}{2})^3=1024\times \frac{1}{8}=128$

Fifth term is $ar^4=(1024)(\frac{1}{2})^4=1024\times \frac{1}{16}=64$

Therefore, the first five terms of G.P if a=1024 and $r=\frac{1}{2}$ are 1024,512,256,128,64.

#Learn more

The sixth term of a geometric sequence is 23 and the tenth term is 5103. find the geometric sequence.

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