Question

find the first 51 terms of AP whose second and third terms are 14 and 18 respectively​

Answer 1

Answer:

5610

Step-by-step explanation:

A2 = 14 and a3 = 18

Common difference = a3 - a2 = 18 - 14 = 4 = d

Now

a2 = a+d=14

a+4=14

a = 10

Now, sum of 51 terms

={51(2a+(50)d)}/2

={51(20+200)}/2

={51×220}/2

=51×110=5610

Therefore sum of 51 terms is 5610

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