Question

find the first derivative of e3x+sinx+logx

Answer 1

e3x*3+cos x + 1/x they says need to type 20 characters

Answer 2

Answer:  We get the first derivative:

$f'(x)=3e^{3x}+\cos x+\frac{1}{x}$

Step-by-step explanation:

Since we have given that

$f(x)=e^{3x}+\sin x+\log x$

We need to take the first derivative of f(x).

As we know that

$\frac{d}{dx}e^{3x}=3e^{3x}\\\\\frac{d}{dx}\sin x=\cos x\\\\\frac{d}{dx}\cos x=-\sin x$

Hence, we get the first derivative:

$f'(x)=3e^{3x}+\cos x+\frac{1}{x}$