Math, asked by MosesIR, 1 month ago

Find the first derivative of the following function using the first principle method:
y = 3x^2 – 2x

Answers

Answered by nikhilreddyaireddy

1

Answer:

Step-by-step explanation:

Attachments:

Answered by Usaidshaikh

0

Answer:

6x –2

Step-by-step explanation:

dy/dx = d/dx ( 3x²– 2x)

= 2×3x – 2

= 6x –2

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