Question

Find the first five term of following given sequences:am=2m^2-3m+1

Answer 1

Answer:

=2m²–3m+1

=2m²–2m–m+1

=2m(m–1) –1( m–1)

=(2m–1)(m–1)

1. (2m–1) =0

2m=1

m=1/2

2. m–1=0

m = 1