Question

Find the first five terms of each sequence. a(1)=48 and a(n)=-0.5(n-1)+8

Answer 1

Answer:

sorry dont know the answer

Answer 2

Answer:

The first five terms of the given geometric sequence are

8

,

40

,

200

,

1000

,

5000

.

Explanation:

The general term for a geometric sequence is

a

n

=

a

1

r

n

−

1

Where

a

n

is the nth term,

a

1

is first term

r

is the common ratio and

n

is the position or number of the term.

Here

a

1

=

8

and

r

=

5

Put

n

=

2

⇒

a

2

=

8

⋅

5

2

−

1

=

8

⋅

5

=

40

Put

n

=

3

⇒

a

3

=

8

⋅

5

3

−

1

=

8

⋅

5

2

=

8

⋅

25

=

200

Put

n

=

4

⇒

a

4

=

8

⋅

5

4

−

1

=

8

⋅

5

3

=

8

⋅

125

=

1000

Put

n

=

5

⇒

a

5

=

8

⋅

5

5

−

1

=

8

⋅

5

4

=

8

⋅

625

=

5000

Hence, the first five terms of the given geometric sequence are

8

,

40

,

200

,

1000

,

5000

.

Step-by-step explanation:

I hope you understand...pls make me as a brainlist answer