find the first five terms of geometric progression a=1024 and r=1/2
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Answered by
5
Answer:
GP=1024,512,256,128,64.
Step-by-step explanation:
we know that;
form of GP is a,ar,ar^2,ar^n-1
so,
a=1024
ar=1024×1/2=512
ar^2=1024×1/4=256
ar^3=1024×1/8=128
ar^4=1024×1/16=64
Answered by
1
Step-by-step explanation:
- a=1024
- r=1/2
formula is
- tn=at^n-1
- t1=1024×1/2^1-1
- 1024×1/2
- t1=512
- t2=1024×1/2
- t2=512
- t3=1024×1/2×1/2
- t3=256
- t4=1024×1/2×1/2×1/2
- t4=128
- t5=1024×1/2×1/2×1/2×1/2
- t5=24
therefore the first five terms are 512,512,256,128,24
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