Math, asked by kanthabadi71, 1 year ago

find the first five terms of GP if a =1024and r=1by2​

Answers

Answered by iamsnehabayal2003
7

refer to the attached file.

thanks for the question!

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Answered by jitendra420156
0

Therefore the first five terms of G.P is

1024,512,256,128 and 64.

Step-by-step explanation:

Given first term (a) = 1024

    common ratio (r) =\frac{1}{2}

N^{th} term of the series is T_n=a r^{n-1}

Second term =T_2=1024\times \frac{1}{2}  = 512

Third term  = T_3=1024 \times( \frac{1}{2} )^2  =256

Fourth term = T_4=1024\times( \frac{1}{2} )^3 =128

Fifth term = T_5=1024\times(\frac{1}{2} )^4  =64

Therefore the first five terms of G.P is

1024,512,256,128 and 64.

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