Question

find the first four consecutive terms in A.p whose sum is 12 and the sum of 3rd and 4th term is14

Answer 1

four terms can be written as a-3d,a-d,a+d,a-3d
s4=12=a-3d+a-d+a+d+a+3d=4a
a=3
sum of 3 and 4 term is 14
14=a+d+a+3d=3+3+4d
4d=8
d=2

Answer 2

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