find the first four term of an A.P. when a=8 and d=-5
Answers
Answer:
a = 8 , d = -5
1st term = a = 8
2nd term = a + d = 8 + (-5) = 3
3rd term = a + 2d = 8 + (2×-5) = 8 + (-10) = -2
4th term = a + 3d = 8 + (3×-5) = 8 + (-15) = -7
So, the first four terms of A.P. is :-
8, 3, -2, -7 .......
The first four terms of AP are 8,3,-2 and -7
Given : In an AP, a = 8 and d = -5
To find : The first four terms of AP.
Solution :
We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the first four terms of AP)
We know that :
Nth term of an AP = a + (N-1) × d
Where,
- a = First term of AP
- d = common difference
In this case,
- a = First term of AP = 8
- d = common difference = -5
1st term of AP = 8 (given data)
Now, applying the above mentioned mathematical formula :
2nd term of AP = 8 + (2-1) × (-5) = 3
3rd term of AP = 8 + (3-1) × (-5) = -2
4th term of AP = 8 + (4-1) × (-5) = -7
Hence, the first four terms of AP are 8,3,-2 and -7