Question

find the first four terms of an ap whose first term is -1 and common difference is 1 by 2

Answer 1

$\boxed{\textbf{\large{Step-by-step explanation:}}}$

◼here we have given first term and common difference of AP ( arithmetic progression)

◼Ap is an Arithmetic progression, where the difference between consecutive terms is constant

first term = a = -1

common difference = d = 1/2

therefor ,

→ t1 = a

t1 = -1

→ t2 = t1 + d = -1 + (1/2)

= -1 /2

→ t3 = t2 + d =( - 1/2 ) + ( 1 /2 )

= ( -1 + 1 ) / 2

= 0 / 2

= 0

→ t4 = t3 + d

= 0 + ( 1/ 2 )

= 1/ 2

Therefor the first four terms of AP (arithmetic progression) are

$\boxed{\textbf{\large{ -1 , ( -1 /2 ) , 0 , ( 1/ 2 )}}}$