Find the first four terms of an Ap whose first term is -3 and the commom difference is -3
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the first term of AP is equal to -3
second term of AP is equal to -3 - 3=(-6)
third term of AP is equal to (-6)-3=(-9)
fourth term of AP is equal to (-9)-3=(-12)
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Answer:
a=-3,
d=-3
a2=a+d
=-3+(-3)
=-6
a3=a+2d
=-3+2(-3)
=-9
a4=a+3d
= -3+3(-3)
= -12
Ap=-3,-6,-9,-12
hope it help you
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