Question

find the first four terms of the sequence whose nth term is ( an = n ^3 -2 )​

Answer 1

Answer:

a1=-1

a2=6

a3=25

a4=62

Step-by-step explanation:

$an = {n}^{3} - 2 \\ n = 1 \\ a1 = {1}^{3} - 2 \\ a1 = 1 - 2 \\ a1 = - 1 \\ n = 2 \\ a2 = {2}^{3} - 2 \\ a2 = 8 -2 \\ a2 = 6 \\ n = 3 \\ a3 = {3}^{3} - 2 \\ a3 = 27 - 2 \\ a3 = 25$

$n = 4 \\ a4 = {4}^{3} - 2 \\ a4 = 64 - 2 \\ a4 = 62$

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Answer 2

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