Find the first, fourth, and eighth terms of the sequence. A(n) = –2 • 2n–1
a) 1; –64; –16,384
b) –2; –16; –256
c) –4; –32; –512
d) –8; –64; –1,024
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Answer:
n
=−2⋅2
n−1
n=1→a
1
=−2⋅2
1−1
=−2⋅2
0
=−2⋅1=−2
n=4→a
4
=−2⋅2
4−1
=−2⋅2
3
=−2⋅8=−16
n=8→a
8
=−2⋅2
8−1
=−2⋅2
7
=−2⋅128=−256
Answer: C.−2; −16; −256
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