Question

find the first,fourth and tenth term of arithmetic discovered by the given rule
A(n) = -6 + (n-1)(6)

a. -6,18,54
b.-6,12,48

Answer 1

substituting the value of n is equal to 1 we get
A(1)=-6
substituting the value of n as 4 we get
A(4)=-6+3(6)
=12
and substituting the value of an equal to 10 we get
A(10)=48