Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
A(n) = 1 + (n –1)(–5.7)
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Given A(n)=1 + (n-1)(-5.7)
for 1st term, n=1
A(1)= 1 + (1-1)(-5.7) = 1 + 0= 1
for 4th term
A(4)= 1 + (4-1)(-5.7)= 1 - 17.1= -16.1
for 10th term
A(10)= 1+ (10-1)(-5.7)= 1- 51.3= -50.3
So the 1st, 4th and 10th terms are 1, -16.1, -50.3.
Hope it helps
for 1st term, n=1
A(1)= 1 + (1-1)(-5.7) = 1 + 0= 1
for 4th term
A(4)= 1 + (4-1)(-5.7)= 1 - 17.1= -16.1
for 10th term
A(10)= 1+ (10-1)(-5.7)= 1- 51.3= -50.3
So the 1st, 4th and 10th terms are 1, -16.1, -50.3.
Hope it helps
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