Question

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n) = 12 + (n–1)(3)

Answer 1

Answer:

$In \: given \: A.P:\\</p><p>First term =A_{1}=12\\</p><p>Fourth \: term =A_{4}=21\\</p><p>Tenth \: term = A_{10}=39$

Step-by-step explanation:

$Given \\ n^{th} \:term \: in \: Arithmetic\: sequence\:\\\boxed{ A_{n}=12+(n-1)3}$

$Now, \\if \: n = 1;\\</p><p>A_{1}= 12+(1-1)3\\=12$

First term =12

$put \:n=4\:in\: A_{n}\: we \: get$

$A_{4}=12+(4-1)3\\=12+3\times 3\\=12+9\\=21$

$put \:n=10\:in\: A_{n}\: we \: get$

$A_{10}=12+(10-1)3\\=12+9\times 3\\=12+27\\=39$

Therefore,

$In \: given \: A.P:\\</p><p>First term =A_{1}=12\\</p><p>Fourth \: term =A_{4}=21\\</p><p>Tenth \: term = A_{10}=39$

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